Fix My Computer, Mark! - when mouse pointer is over that link, an image is pop up

when mouse pointer is over that link, an image is pop up

To create a hover effect in PHP where an image pops up when you hover over a link, you'll primarily use HTML, CSS, and potentially a bit of JavaScript. PHP is not directly involved in this type of front-end interaction, but you can use it to serve content dynamically if needed.

Here’s a simple example using HTML and CSS:

HTML

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Hover Image Popup</title>
<link rel="stylesheet" href="/styles.css">
</head>
<body>
<div class="image-popup">
<a href="#">Hover over me</a>
<div class="popup-image">
<img src="/your-image.jpg" alt="Popup Image">
</div>
</div>
</body>
</html>

CSS (`styles.css`)

.image-popup {
position: relative;
display: inline-block;
}

.popup-image {
visibility: hidden;
width: 200px; /* Adjust as needed */
position: absolute;
bottom: 125%; /* Adjust as needed */
left: 50%;
transform: translateX(-50%);
z-index: 1;
}

.popup-image img {
border: 1px solid #ddd; /* Optional: Add a border */
border-radius: 4px; /* Optional: Add rounded corners */
}

.image-popup:hover .popup-image {
visibility: visible;
}

Explanation:
1. HTML: Contains a link and a div for the popup image. The popup-image div is the one that shows the image on hover.
2. CSS:

.image-popup sets the position of the container to relative, which is necessary for the absolute positioning of the image.
.popup-image starts off hidden (visibility: hidden) and is positioned absolutely relative to the .image-popup container.
.image-popup:hover .popup-image makes the popup visible when the mouse hovers over the .image-popup container.

Make sure to replace your-image.jpg with the path to your image file. Adjust the CSS properties to fit your design needs, such as width, positioning, or border styles.

Scripts

when mouse pointer is over that link, an image is pop up